JEE Main 2016ChemistryStates of MatterMediumMCQ

JEE Main 2016States of Matter Question with Solution

JEE Main 2016 (10 Apr Online)

Question

Initially, the root-mean-square (RMS) velocity of N2 molecules at certain temperature is u. If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new RMS velocity will be:

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Show full solutionCorrect option: A
Correct answer
A2 u

Step-by-step explanation

u=3RT28

u=3R×2T14

uu=14

uu=12

u=2u

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About this question

This is a previous-year question from JEE Main 2016, covering the States of Matter chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.