JEE Main 2023ChemistryStates of MatterEasyNumerical

JEE Main 2023 — States of Matter Question with Solution

JEE Main 2023 (13 Apr Shift 1)

Question

A certain quantity of real gas occupies a volume of 0.15 dm3 at 100 atm and 500 K when its compressibility factor is 1.07. Its volume at 300 atm and 300 K (When its compressibility factor is 1.4) is ______×10-4dm3(Nearest integer)

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Show full solutionCorrect answer: 392
Correct answer
392

Step-by-step explanation

The compressibility factor (Z) is given as:

Z = PVnRT

n=PVZRT

Z1=1.07, P1=100atm, V1=0.15L, T1=500KZ2=1.4, P1=300atm, V2=?, T2=300K

Z1Z2=P1V1×T2T1×P2V2

1.071.4=100×0.15×300500×300×V2

V2=0.03925 dm3

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About this question

This is a previous-year question from JEE Main 2023, covering the States of Matter chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.