JEE Main 2022ChemistryStates of MatterEasyNumerical

JEE Main 2022 — States of Matter Question with Solution

JEE Main 2022 (25 Jul Shift 1)

Question

The pressure of a moist gas at 27°C is 4 atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is …×10-1 atm. (Nearest integer)
(Given: The vapour pressure of water at 27°C is 0.4 atm)

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Show full solutionCorrect answer: 22
Correct answer
22

Step-by-step explanation

Dalton's Law states that the total pressure P of moist air is the sum of partial pressures of dry air Pa and water vapor Pv: P= Pa+Pv. Only the absolute pressure is the state parameter of moist air.

Pgas+PH2O=4

Pgas=4-0.4=3.6 atm

As volume is doubled, Pgasnew =1.8 atm

New Total Pressure =1.8+0.4=2.2 atm

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About this question

This is a previous-year question from JEE Main 2022, covering the States of Matter chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.