JEE Main 2021ChemistryStates of MatterMediumNumerical

JEE Main 2021 — States of Matter Question with Solution

JEE Main 2021 (17 Mar Shift 1)

Question

The pressure exerted by a non-reactive gaseous mixture of 6.4 g of methane and 8.8 g of carbon dioxide in a 10 L vessel at 27°C is _____kPa. (Round off to the Nearest Integer).

[Assume gases are ideal, R=8.314 J mol-1 K-1 Atomic masses: C :12.0 u, H :1.0 u,  O :16.0 u]

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Show full solutionCorrect answer: 150
Correct answer
150

Step-by-step explanation

Total moles of gases, n=nCH4+nCO2

=6.416+8.844=0.6

Now, P=nRTV=0.6×8.314×30010×10-3

=1.49652×105 Pa=149.652 kPa

≈150 kPa

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About this question

This is a previous-year question from JEE Main 2021, covering the States of Matter chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.