JEE Main 2014ChemistryStates of MatterMediumMCQ

JEE Main 2014 — States of Matter Question with Solution

JEE Main 2014 (19 Apr Online)

Question

Sulphur dioxide and oxygen were allowed​ to diffuse through a porous partition. 20 dm3 of SO2 diffuses through the porous partition in 60 seconds. The volume of O2 in dm3 which diffuses under the similar condition in 30 seconds will be (atomic mass of sulphur= 32 u);

Choose an option

Show full solutionCorrect option: C
Correct answer
C14.1

Step-by-step explanation

As per Graham's law,

V SO 2 / t SO 2 V O 2 / t O 2 = p SO 2 p O 2 M O 2 M SO 2 = M O 2 M SO 2

2 0 dm 3 / 6 0 sec V O 2 / 3 0 sec = 3 2 6 4 = 1 1 · 4 1 4

2 0 × 3 0 6 0 × V O 2 = 1 1 · 4 1 4 ⇒ V O 2 = 1 0 × 1 · 4 1 4

= 14.14 dm3

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the States of Matter chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2014, covering the States of Matter chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.