JEE Main 2024 — Hydrocarbons Question with Solution

When haloalkane or alkyl halide with a β hydrogen is heated with alcoholic solution of $\mathrm{KOH}$, elimination of a hydrogen atom from $\mathrm{\beta }$ carbon and halogen atom from $\mathrm{\alpha }-$carbon occurs as a result, alkene is formed as product. Since $\mathrm{\beta }$ hydrogen atom is involved in the elimination reaction, it is often called $\mathrm{\beta }$ elimination. An alkene is formed. This alkene then on reaction with $\mathrm{HBr}$ undergoes addition reaction to give bromopropane, which on reaction with aqueous $\mathrm{KOH}$ gives alcohol, propan$-2-$ol.