JEE Main 2019ChemistryHydrocarbonsMediumMCQ

JEE Main 2019 — Hydrocarbons Question with Solution

JEE Main 2019 (12 Apr Shift 2)

Question

Heating of 2-chloro-1-phenylbutane with EtOK/EtOH gives X as the major product. Reaction X with Hg(OAc)2/H2O followed by NaBH4 gives Y as the major product. Y is:

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Correct answer
A

Step-by-step explanation

EtOK is potassium ethylene oxide and it is colourless gas and is liquid at low temperatures and is highly flammable i.e. that catches fire easily and undergoes alkylation reactions with many organic compounds and EtOH is the ethanol.

The heating of 2-chloro-1-phenylbutane  with EtOK/EtOHgives X as the major product. Reaction X with Hg(OAc)2/H2Ofollowed by NaBH4 gives Y as the major product. Y is 1-phenylbutanol.

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About this question

This is a previous-year question from JEE Main 2019, covering the Hydrocarbons chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.