JEE Main 2014PhysicsThermodynamicsEasyMCQ

JEE Main 2014 — Thermodynamics Question with Solution

JEE Main 2014 (06 Apr)

Question

One mole of diatomic ideal gas undergoes a cyclic process ABC as shown in figure. The process BC is adiabatic. The temperatures at A, B and C are 400 K, 800 K and 600 K respectively. Choose the correct statement :

Choose an option

Show full solutionCorrect option: D
Correct answer
DThe change in internal energy in the process BC is  - 500 R

Step-by-step explanation



Δ U CA = nc v T A - T C = 1 × 5 2 R - 2 0 0 = - 5 0 0 R

Δ U AB = nc v T B - T A = 1 × 5 2 R × 4 0 0 = + 1 0 0 0 R

Δ U BC = nc v T C - T B = 1 × 5 2 R - 2 0 0 = - 5 0 0 R

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About this question

This is a previous-year question from JEE Main 2014, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.