JEE Main 2026 — Thermodynamics Question with Solution
JEE Main 2026 (23 January Shift 2)
Question
One mole of an ideal diatomic gas expands from volume to 2 V isothermally at a temperature and does joule of work. If the gas undergoes same magnitude of expansion adiabatically from doing the same amount of work , then its final temperature will be (close to) .
Choose an option
Show full solutionCorrect option: D
Correct answer
D-56
Step-by-step explanation
For isothermal expansion of 1 mole diatomic gas from V to 2V at 300 K:
For adiabatic expansion with same volume change and same work output:
For diatomic gas, . Setting work equal:
Simplifying:
, so
, giving K -56°C.
For adiabatic expansion with same volume change and same work output:
For diatomic gas, . Setting work equal:
Simplifying:
, so
, giving K -56°C.
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