JEE Main 2018PhysicsThermodynamicsHardMCQ

JEE Main 2018 — Thermodynamics Question with Solution

JEE Main 2018 (16 Apr Online)

Question

One mole of an ideal monatomic gas is taken along the path ABCA as shown in the PV diagram. The maximum temperature attained by the gas along the path BC is given by:

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Show full solutionCorrect option: C
Correct answer
C258 P0V0R

Step-by-step explanation

Equation of the line BC, P=P0-2P0V0(V-2V0), the temperature = P0V- 2P0V2V0+4P0V1 ×R⇒T=P0R5V-2V2V0⇒dTdV=0
⇒5-4VV0=0⇒V=54V0
⇒T=P0R5×5V04-2V0×2516V02⇒T=258P0V0R.

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About this question

This is a previous-year question from JEE Main 2018, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.