JEE Main 2022PhysicsThermodynamicsEasyMCQ

JEE Main 2022Thermodynamics Question with Solution

JEE Main 2022 (29 Jun Shift 2)

Question

Starting with the same initial conditions, an ideal gas expands from volume V1 to V2 in three different ways. The work done by the gas is W1 if the process is purely isothermal, W2, if the process is purely adiabatic and W3 if the process is purely isobaric. Then, choose the correct option

Choose an option

Show full solutionCorrect option: A
Correct answer
AW2<W1<W3

Step-by-step explanation

As we know, in isobaric process pressure remains constant and magnitude of slope of adiabatic curve will be more than the isothermal curve at the common point, therefore diagram for process will be as given below.

Also, W= area under P-V curve.

Hence,

 W2<W1<W3

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About this question

This is a previous-year question from JEE Main 2022, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.