JEE Main 2021PhysicsThermodynamicsMediumMCQ

JEE Main 2021 — Thermodynamics Question with Solution

JEE Main 2021 (17 Mar Shift 1)

Question

A Carnot's engine working between 400 K and 800 K has a work output of 1200 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is:

Choose an option

Show full solutionCorrect option: D
Correct answer
D2400 J

Step-by-step explanation

η=T2 T1=Q2Q1=Q1-WQ1  ∵W=Q1-Q2

400800=1-WQ1

WQ1=1-12=12

Q1=2 W=2400 J

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About this question

This is a previous-year question from JEE Main 2021, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.