JEE Main 2019PhysicsThermodynamicsHardMCQ

JEE Main 2019 — Thermodynamics Question with Solution

JEE Main 2019 (10 Apr Shift 2)

Question

One mole of an ideal gas passes through a process where pressure and volume obey the relation  P=Po1-12VoV2 . Here Po and Vo are constants. Calculate the change in the temperature of the gas if its volume changes from Vo  to  2Vo .

Choose an option

Show full solutionCorrect option: B
Correct answer
B54P0V0R

Step-by-step explanation

For ideal gas, PV=nRT
Therefore, nRTV=P01-12V0V2
⇒ T=P0VR1-12V0V2
Therefore, the change in temperature is:
ΔT=Tf-Ti
=P02V0R1-12V02V02-P0VR1-V022V02
=5P0V04R

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About this question

This is a previous-year question from JEE Main 2019, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.