JEE Main 2020PhysicsThermodynamicsHardMCQ

JEE Main 2020Thermodynamics Question with Solution

JEE Main 2020 (07 Jan Shift 2)

Question

Two ideal Carnot engines operate in cascade (all heat given up by one engine is used by the other engine to produce work) between temperatures, T1 and T2 . The temperature of the hot reservoir of the first engine is T1 and the temperature of the cold reservoir of the second engine is T2 . T is temperature of the sink of first engine which is also the source for the second engine. How is T related to T1 and T2 , if both the engines perform equal amount of work?

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Show full solutionCorrect option: B
Correct answer
BT=T1+T22

Step-by-step explanation

Q1: Heat input to Ist engine
Q: Heat rejected from Ist engine
Q2: Heat rejected from IInd engine
Work done by Ist engine = work done by IInd engine.
Q-Q2=Q1-Q
2Q=Q1+Q2
2=T1T+T2T
T=T1+T22

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About this question

This is a previous-year question from JEE Main 2020, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.