JEE Main 2018PhysicsThermodynamicsEasyMCQ

JEE Main 2018Thermodynamics Question with Solution

JEE Main 2018 (15 Apr)

Question

One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27oC . The magnitude of work done on the gas will be:

Choose an option

Show full solutionCorrect option: B
Correct answer
B300Rln2

Step-by-step explanation

Work done on gas=nRTlnPfPi=R(300)ln(2)=300Rln2.

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About this question

This is a previous-year question from JEE Main 2018, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.