JEE Main 2020PhysicsThermodynamicsEasyMCQ

JEE Main 2020 — Thermodynamics Question with Solution

JEE Main 2020 (08 Jan Shift 2)

Question

A Carnot engine having an efficiency of 110 is being used as a refrigerator. If the work done on the refrigerator is 10 J, the amount of heat absorbed from the reservoir at a lower temperature is

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Show full solutionCorrect option: D
Correct answer
D90 J

Step-by-step explanation

For Carnot engine using as refrigerator
W=Q2T1T2-1
It is given η=110⇒η=1-T2T1⇒T2T1=910
So ,Q2=90 J as W=10 J

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About this question

This is a previous-year question from JEE Main 2020, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.