JEE Main 2015PhysicsThermodynamicsEasyMCQ

JEE Main 2015Thermodynamics Question with Solution

JEE Main 2015 (10 Apr Online)

Question

An ideal gas goes through a reversible cycle abcd has the V - T diagram shown below. Process da and bc are adiabatic.



The corresponding P - V diagram for the process is (all figures are schematic and not drawn to scale) :

Choose an option

Show full solutionCorrect option: A
Correct answer
A

Step-by-step explanation

Is an adiabatic process

TVγ-1=constVT1γ-1=const

as T increase V decreases at non-uniform rate

In process ab P = constant as VT

In process cd P= constant s VT

But since slope of V - T graph 1P

since slope of ab < slope of cd

Pab>Pcd

Also in adiabatic process da as T is increasing V in decreasing

P is increasing, so P - V diagram is as below

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Thermodynamics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2015, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.