JEE Main 2023PhysicsThermodynamicsEasyMCQ

JEE Main 2023 — Thermodynamics Question with Solution

JEE Main 2023 (12 Apr Shift 1)

Question

An engine operating between the boiling and freezing points of water will have

A. Efficiency more than 27%.

B. Efficiency less than the efficiency of a Carnot engine operating between the same two temperatures.

C. Efficiency equal to 27%.

D. Efficiency less than 27%.

Choose the correct answer from the options given below

Choose an option

Show full solutionCorrect option: C
Correct answer
CB and D only

Step-by-step explanation

The efficiency of Carnot engine can be calculated as follows:

ηC=1-273373×100%=26.8%

Hence, the efficiency of the engine is given by

ηengine<ηcarnot.

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About this question

This is a previous-year question from JEE Main 2023, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.