JEE Main 2014PhysicsSemiconductorsEasyMCQ

JEE Main 2014 — Semiconductors Question with Solution

JEE Main 2014 (09 Apr Online)

Question

Identify the gate and match A,B,Y in the bracket to check.

    

Choose an option

Show full solutionCorrect option: D
Correct answer
DAND (A=1, B=1, Y=1)

Step-by-step explanation

The output of the first NAND gate

Y'=A·B¯

The output of the second NAND gate

Y=A·B¯·A·B¯¯⇒ Y=A·B¯¯+A·B¯¯⇒ Y=A·B

So, the equivalent circuit will be an AND gate.

AND (A=1, B=1, Y=1)

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About this question

This is a previous-year question from JEE Main 2014, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.