JEE Main 2016PhysicsSemiconductorsEasyMCQ

JEE Main 2016Semiconductors Question with Solution

JEE Main 2016 (09 Apr Online)

Question

The truth table given in fig. represents:
A B Y
0 0 0
0 1 1
1 0 1
1 1 1

Choose an option

Show full solutionCorrect option: A
Correct answer
AOR-Gate

Step-by-step explanation

The given truth table represents OR gate.

Its boolean algebra is Y=A+B, where A and B are input and Y is output.

OR gate gives output 1 if any one of its input is 1

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Semiconductors chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2016, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.