JEE Main 2019PhysicsSemiconductorsMediumMCQ

JEE Main 2019 — Semiconductors Question with Solution

JEE Main 2019 (12 Apr Shift 1)

Question

The transfer characteristic curve of a transistor, having input and output resistance 100 Ω and 100 kΩ respectively, is shown in the figure. The voltage and power gain, are respectively:

Choose an option

Show full solutionCorrect option: A
Correct answer
A5×104, 2.5×106

Step-by-step explanation

Current gain β=ΔICΔIB= 5 ×10-3 100 ×10-6=50
Voltage gain (AV)=βRoutRin=50×100×103100=5×104
Power gain =AV×β=50×5×104=2.5×106

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About this question

This is a previous-year question from JEE Main 2019, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.