JEE Main 2021PhysicsSemiconductorsEasyMCQ

JEE Main 2021 — Semiconductors Question with Solution

JEE Main 2021 (27 Aug Shift 2)

Question

For a transistor α and β are given as α=ICIE and β=ICIB. Then the correct relation between α and β will be:

Choose an option

Show full solutionCorrect option: C
Correct answer
Cβ=α1-α

Step-by-step explanation

In the case of the transistor the relation between emitter current, base current and, the collector current is, iE=iB+iC, ⇒iEiC=iBiC+1, 

⇒1α=1β+1

⇒β=α1-α

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Semiconductors chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.