JEE Main 2022PhysicsSemiconductorsMediumMCQ

JEE Main 2022 — Semiconductors Question with Solution

JEE Main 2022 (28 Jul Shift 2)

Question

An n.p.n transistor with current gain β=100 in common emitter configuration is shown in figure. The output voltage of the amplifier will be

Choose an option

Show full solutionCorrect option: B
Correct answer
B1.0 V

Step-by-step explanation

We know that, Voltage gain=Output voltageInput voltage

Then, Vout=Vin×voltage gain.

Vout=Vin×Current gain×resistance gain

Vout=Vin ×β×Rout Rin 

Vout =100×10×103103×10-3

=1 V

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Semiconductors chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.