JEE Main 2020PhysicsSemiconductorsMediumNumerical

JEE Main 2020Semiconductors Question with Solution

JEE Main 2020 (09 Jan Shift 2)

Question

In the circuit shown below, is working as a 8 V dc regulated voltage source. When 12 V is used as an input, the power dissipated (in mW ) in each diode is (Considering both zener diodes are identical) 

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Show full solutionCorrect answer: 40
Correct answer
40

Step-by-step explanation

i=12-8200+200A=4400=10-2 A
Power loss in each diode=410-2 W=40 mW

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About this question

This is a previous-year question from JEE Main 2020, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.