JEE Main 2019PhysicsSemiconductorsMediumMCQ

JEE Main 2019 — Semiconductors Question with Solution

JEE Main 2019 (10 Apr Shift 2)

Question

The figure represents a voltage regulator circuit using a Zener diode. The breakdown voltage of the Zener diode is 6 V and the load resistance is, RL=4 kΩ . The series resistance of the circuit is  Ri=1 kΩ . If the battery voltage VB varies from 8 V  to  16 V , what are the minimum and maximum values of the current through Zener diode?

Choose an option

Show full solutionCorrect option: C
Correct answer
C0.5 mA; 8.5 mA

Step-by-step explanation

For V0=8V

8 V-1000 i0=6 V
i0=2 mA
i0-i1=64000=1.5 mA
i1=0.5 mA
For V0=16 V

16 V-1000 i0=6 V
i0=10 mA
i0-i2=64000=1.5 mA
i2=8.5 mA

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About this question

This is a previous-year question from JEE Main 2019, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.