JEE Main 2023 — Semiconductors Question with Solution
JEE Main 2023 (24 Jan Shift 2)
Question
The logic gate equivalent to the given circuit diagram is :
Choose an option
Show full solutionCorrect option: B
Step-by-step explanation
When both switches are open, the current will flow through the bulb and it will glow.
When switch A is closed and switch B is open, the current will flow through the bulb and it will glow.
When switch A is open and switch B is closed, the current will flow through bulb and it will glow.
When both the switches are closed, since the resistance of left arm of circuit is negligible, the current will flow through the left arm and hence the bulb will not glow.
The truth table is given as:
| A | B | Bulb |
| 0 | 0 | 1 |
| 1 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 1 | 0 |
Which shows that the given circuit is a NAND gate.
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This is a previous-year question from JEE Main 2023, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.