JEE Main 2023PhysicsSemiconductorsHardMCQ

JEE Main 2023 — Semiconductors Question with Solution

JEE Main 2023 (08 Apr Shift 2)

Question

For a given transistor amplifier circuit in CE configuration VCC=1 V,RC=1 kΩ,Rb=100 kΩ and β=100. Value of base current Ibis

Choose an option

Show full solutionCorrect option: D
Correct answer
DIb=10 μA

Step-by-step explanation

Considering the transistor in saturation mode, VCE=0

Using Kirchhoff's voltage rule,

-ICRC+VCC=0⇒IC=VCCRC⇒IC=1 V103 Ω=10-3 A

So, 

β=ICIb=10-3 AIb⇒Ib=10-3102=10-5 A=10 μA

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About this question

This is a previous-year question from JEE Main 2023, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.