JEE Main 2015PhysicsMotion In One DimensionMediumMCQ

JEE Main 2015Motion In One Dimension Question with Solution

JEE Main 2015 (04 Apr)

Question

Two stones are thrown up simultaneously from the edge of a cliff 240 m high with an initial speed of 10 m s-1 and 40 m s-1 respectively. Which of the following graph best represents the time variation of the relative position of the second stone with respect to the first? (Assume stones do not rebound after hitting the ground and neglect air resistance, take g=10 ms-2)(the figure are schematic and not drawn to scale)

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Show full solutionCorrect option: D
Correct answer
D

Step-by-step explanation

S1=10t-12gt2. When S1=-240t=8s. So, at t=8 seconds first stone will reach the ground. S2=40t-12gt2. Till t=8 sS2-S1=30t. But after 8 s S1 is constant =-240. Relative to stone 1 for (t1>8) s displacements of stone 2S2+240. And at t=12 s seconds stone will reach the ground. The corresponding graph of the relative position of second stone with respect to first is, 


 

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About this question

This is a previous-year question from JEE Main 2015, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.