JEE Main 2026 — Motion In One Dimension Question with Solution

The v-x graph shows velocity decreasing linearly with distance. Using kinematic equation $v^2=v_0^2+2ax$, we can establish the relationship between acceleration and position.
From the linear v-x relationship, differentiating using $a=v\frac{dv}{dx}$ yields acceleration that is linearly proportional to distance from the origin.
The a-x graph shows a straight line passing through the origin with positive slope, indicating that acceleration increases linearly with distance while remaining positive throughout the motion.