JEE Main 2021PhysicsMotion In One DimensionMediumMCQ

JEE Main 2021Motion In One Dimension Question with Solution

JEE Main 2021 (17 Mar Shift 2)

Question

The velocity of a particle is v=v0+gt+Ft2 m s-1. Its position is x=0 at t=0 ; then its displacement after time (t=1 s) is :

Choose an option

Show full solutionCorrect option: B
Correct answer
Bv0+g2+F3

Step-by-step explanation

v=v0+gt+Ft2

dsdt=v0+gt+Ft2

ds=01v0+gt+Ft2dt

s=v0t+gt22+Ft3301

s=v0+g2+F3

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Motion In One Dimension chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.