JEE Main 2023PhysicsMotion In One DimensionMediumMCQ

JEE Main 2023 — Motion In One Dimension Question with Solution

JEE Main 2023 (06 Apr Shift 2)

Question

As shown in the figure, a particle is moving with constant speed π m s-1. Considering its motion from A to B, the magnitude of the average velocity is:

Choose an option

Show full solutionCorrect option: C
Correct answer
C1.53 m s-1

Step-by-step explanation

The given data is 

v=π m s-1

By using trigonometric ratios in the triangle shown above the displacement can be found out by

sin60°=AB2R⇒AB=R3

The formula for distance is 

d=vt⇒t=dv⇒t=120°360°×2πRπ=2R3

So, the average velocity is 

vavg=3R2R3=332

=1.53 m s-1

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About this question

This is a previous-year question from JEE Main 2023, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.