JEE Main 2024PhysicsMotion In One DimensionHardMCQ

JEE Main 2024 — Motion In One Dimension Question with Solution

JEE Main 2024 (29 Jan Shift 1)

Question

A body starts moving from rest with constant acceleration covers displacement S1 in first (p-1) seconds and S2 in first p seconds. The displacement S1+S2 will be made in time :

Choose an option

Show full solutionCorrect option: B
Correct answer
B2p2-2p+1 s

Step-by-step explanation

For the displacement S1 of the body, it can be written that

S1=12a(p-1)2   ...1

And, for the displacement S2 of the body, it follows that

S2=12a(p)2   ...2

If t be the required time, it follows that

S1+S2=12at2   ...3

Equations (1), (2) and (3) imply that

(p-1)2+p2=t2⇒t=2p2-2p+1 s

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Motion In One Dimension chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2024, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.