JEE Main 2024PhysicsMotion In One DimensionMediumNumerical

JEE Main 2024 — Motion In One Dimension Question with Solution

JEE Main 2024 (27 Jan Shift 2)

Question

A body falling under gravity covers two points A and B separated by 80 m in 2 s. The distance of upper point A from the starting point is _____m. Use g=10 m s-2

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Show full solutionCorrect answer: 45
Correct answer
45

Step-by-step explanation

From A→B, using the equation of motion, we have

-80=-v1t-12×10t2⇒-80=-2v1-12×10×22⇒-80=-2v1-20⇒-60=-2v1⇒v1=30 m s-1

From O to A, it follows that

v2=u2+2gS⇒302=0+2×(-10)(-S)⇒900=20 S⇒S=45 m

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About this question

This is a previous-year question from JEE Main 2024, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.