JEE Main 2022PhysicsMotion In One DimensionMediumNumerical

JEE Main 2022 — Motion In One Dimension Question with Solution

JEE Main 2022 (26 Jun Shift 2)

Question

A ball is projected vertically upward with an initial velocity of 50 m s-1 at t=0 s. At t=2 s, another ball is projected vertically upward with same velocity. At t=____s, second ball will meet the first ball g=10 m s-2.

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Show full solutionCorrect answer: 6
Correct answer
6

Step-by-step explanation

Distance covered by ball A is h=502-12×10×22=100-20=80 m

Now, at time t=2 s, velocity of A is vA=50-10×2=30 m s-1

Relative velocity of both balls after 2 s is vrel=50-30=20 m s-1

Here, relative displacement xrel=80 m s-1 and relative accelerationarel=0.

Time taken t=8020=4 s

Time at which they will meet is t=4+2=6 s

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About this question

This is a previous-year question from JEE Main 2022, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.