JEE Main 2025 — Mechanical Properties of Solids Question with Solution
JEE Main 2025 (24 Jan Shift 2)
Question
The increase in pressure required to decrease the volume of a water sample by is . Bulk modulus of water is . The value of P is
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Show full solutionCorrect answer: 43
Correct answer
43
Step-by-step explanation
Since bulk modulus is given as
$\begin{aligned}
& \mathrm{B}=\frac{-\Delta \mathrm{P}}{\left(\frac{\Delta \mathrm{~V}}{\mathrm{~V}}\right)} \\
& 2.15 \times 10^9=\frac{-\Delta \mathrm{P}}{-\left(\frac{0.2}{100}\right)} \\
& \Delta \mathrm{P}=2.15 \times 10^9 \times 2 \times 10^{-3} \\
& =4.3 \times 10^6=43 \times 10^5 \mathrm{~N} / \mathrm{m}^2
\end{aligned}$
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This is a previous-year question from JEE Main 2025, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.