JEE Main 2026 — Mechanical Properties of Solids Question with Solution
JEE Main 2026 (06 April Shift 2)
Question
Figure represents the extension () of a wire of length meter, suspended from the ceiling of the room at one end with a load connected to the other end. If the cross-sectional area of the wire is m then the Young's modulus of the wire is __________ N/m.
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
From the given graph, we can observe that for a load N, the extension is m.
The formula for Young's modulus is:
Given:
Length of the wire, m
Cross-sectional area, m
Substituting the values into the formula:
N/m
Answer:
The formula for Young's modulus is:
Given:
Length of the wire, m
Cross-sectional area, m
Substituting the values into the formula:
N/m
Answer:
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This is a previous-year question from JEE Main 2026, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.