JEE Main 2023PhysicsMechanical Properties of SolidsMediumNumerical

JEE Main 2023 — Mechanical Properties of Solids Question with Solution

JEE Main 2023 (25 Jan Shift 1)

Question

As shown in the figure, in an experiment to determine Young's modulus of a wire, the extension-load curve is plotted. The curve is a straight line passing through the origin and makes an angle of 45° with the load axis. The length of wire is 62.8 cm and its diameter is 4 mm. The Young's modulus is found to be  x×104 N m-2

The value of x is _______.

Enter your answer

Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

Given here, L=62.8 cm and d=4 mm.

From the given graph, we can see that extension in wire is linearly dependent on force applied. Slope of the curve is tan45°=1.

So, F=ΔL

Young's modulus is given by Y=FLAΔL, where, A is area of wire.

⇒Y=LA

⇒Y=62.8×10-2π2×10-32

⇒Y=5×104 N m-2

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Mechanical Properties of Solids chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.