JEE Main 2020PhysicsMechanical Properties of SolidsEasyMCQ

JEE Main 2020 — Mechanical Properties of Solids Question with Solution

JEE Main 2020 (04 Sep Shift 2)

Question

A cube of metal is subjected to a hydrostatic pressure 4 GPa. The percentage change in the length of the side of the cube is close to : (Given bulk modulus of metal, B=8×1010 Pa)

Choose an option

Show full solutionCorrect option: D
Correct answer
D1.67

Step-by-step explanation

B=-∆P∆VV
∆VV=-∆PB
Magnitude is given by,
∆VV=∆PB

Volume in terms of length can be represented as,

3×∆LL=∆PB

Therefore,

∆LL=13×∆PB

Substituting the values we get,
∆LL=13×4×1098×1010=160

Percantage change is,
160×100=53=1.67

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About this question

This is a previous-year question from JEE Main 2020, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.