JEE Main 2022PhysicsMechanical Properties of SolidsMediumMCQ

JEE Main 2022 — Mechanical Properties of Solids Question with Solution

JEE Main 2022 (27 Jul Shift 2)

Question

A steel wire of length 3.2 mYS=2.0×1011 N m-2 and a copper wire of length 4.4 m YC=1.1×1011 N m-2 , both of radius 1.4 mm are connected end to end. When stretched by a load, the net elongation is found to be 1.4 mm. The load applied, in Newton, will be: (Given π=227)

Choose an option

Show full solutionCorrect option: D
Correct answer
D154

Step-by-step explanation

When two wires are connected end to end, the tension in them will be same.

Change in length using Hooke's law can be found as,

Y=FlA∆l⇒Δl=FlAY

Total change in length can be written as,

Δl=Δl1+Δl2   

⇒Δl=Fl1 A1Y1+Fl2 A2Y2

⇒F=Δll1 A1Y1+l2 A2Y2=1.4×10-33.2π1.4×10-32×2.0×1011+4.4π1.4×10-32×1.1×1011⇒F=1.54×102=154 N

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About this question

This is a previous-year question from JEE Main 2022, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.