JEE Main 2021PhysicsMechanical Properties of SolidsEasyMCQ

JEE Main 2021 — Mechanical Properties of Solids Question with Solution

JEE Main 2021 (31 Aug Shift 1)

Question

A uniform heavy rod of weight 10 kg m s-2, cross-sectional area 100 cm2 and length 20 cm is hanging from a fixed support. Young modulus of the material of the rod is 2×1011 N m-2. Neglecting the lateral contraction, find the elongation of rod due to its own weight:

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Show full solutionCorrect option: A
Correct answer
A5×10-10 m

Step-by-step explanation

Elongation due to self weight,
Wl2AY=10×0.22×2×1011×100×10-4=5×10-10 m

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About this question

This is a previous-year question from JEE Main 2021, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.