JEE Main 2019PhysicsMechanical Properties of FluidsMediumMCQ

JEE Main 2019 — Mechanical Properties of Fluids Question with Solution

JEE Main 2019 (10 Apr Shift 2)

Question

Water from a tap emerges vertically downwards with an initial speed of  1.0 ms-1 . The cross - sectional area of the tap is  10-4 m2 . Assume that the pressure is constant throughout the stream of water and that the flow is streamlined. The cross - sectional area of the stream, 0.15 m below the tap would be:
(Take  g=10 ms-2 )

Choose an option

Show full solutionCorrect option: D
Correct answer
D5×10-5 m2

Step-by-step explanation

Velocity of water after falling through distance 0.15 m is
v2=u2+2as
=1+2×10×0.15
v2=4
v=2 m/s
From equation of continuity
A1v1=A2v2
A2=10-4×12=5×10-5 m2

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About this question

This is a previous-year question from JEE Main 2019, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.