JEE Main 2026 — Mechanical Properties of Fluids Question with Solution
JEE Main 2026 (04 April Shift 1)
Question
The surface tension of a soap solution is N/m. The work required to increase the radius of a soap bubble from cm to cm is J. The value of is _____. ()
Enter your answer
Show full solutionCorrect answer: 264
Correct answer
264
Step-by-step explanation
The work done to increase the radius of a soap bubble is given by
Since a soap bubble has two free surfaces, the change in surface area is
Substituting the given values:
Using :
J
Comparing with J, we get
Answer:
Since a soap bubble has two free surfaces, the change in surface area is
Substituting the given values:
Using :
J
Comparing with J, we get
Answer:
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Mechanical Properties of Fluids chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2026, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.