JEE Main 2023PhysicsMechanical Properties of FluidsHardNumerical

JEE Main 2023 — Mechanical Properties of Fluids Question with Solution

JEE Main 2023 (24 Jan Shift 2)

Question

A spherical ball of radius 1 mm and density 10.5 g cc-1 is dropped in glycerine of coefficient of viscosity 9.8 poise and density 1.5 g cc-1. Viscous force on the ball when it attains constant velocity is 3696×10-x N. The value of x is

(Given, g=9.8 m s-2 and π=227)

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Show full solutionCorrect answer: 7
Correct answer
7

Step-by-step explanation

Viscous force on the ball when it attains constant velocity i.e., terminal velocity is,

 Fv=mg-FB  As, a=0

Here, FB is buoyant force.

⇒Fv=Vρbg-Vρgg=Vgρb-ρg=43π10-33×9.810.5-1.5×103≈3696×10-7 N

Thus, x=7.

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About this question

This is a previous-year question from JEE Main 2023, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.