JEE Main 2022PhysicsMechanical Properties of FluidsHardNumerical

JEE Main 2022 — Mechanical Properties of Fluids Question with Solution

JEE Main 2022 (27 Jul Shift 2)

Question

A spherical soap bubble of radius 3 cm is formed inside another spherical soap bubble of radius 6 cm. If the internal pressure of the smaller bubble of radius 3 cm in the above system is equal to the internal pressure of the another single soap bubble of radius r cm. The value of r is _____

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Show full solutionCorrect answer: 2
Correct answer
2

Step-by-step explanation

Pressure inside a bubble is given by, P0+4Tr.

Pressure inside the bubble of smaller radius will be, 

P2-P1=P0+4T6+4T3

Pressure inside the bubble with radius r, P0+4Tr

Now,

⇒P0+4T6+4T3=P0+4Tr

⇒1r=16+13

⇒r=2 cm

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About this question

This is a previous-year question from JEE Main 2022, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.