JEE Main 2014PhysicsMechanical Properties of FluidsEasyMCQ

JEE Main 2014 — Mechanical Properties of Fluids Question with Solution

JEE Main 2014 (19 Apr Online)

Question

In the diagram shown, the difference in the two tubes of the manometer is 5 cm, the cross-section of the tube at A and B is 6 mm2 and 10 mm2 respectively. The rate at which water flows through the tube is g=10 m s-2

Choose an option

Show full solutionCorrect option: A
Correct answer
A7.5 cc s-1

Step-by-step explanation

6vA=10vB  ......1

12ρvA2-ρgh=12ρvB2  .........(2)

⇒vA=10.8 m s-1 

 dVdt=AvA

=6×10-2 cm2×1000.8 cm s-1=7.5 cc s-1

OR

By the concept of the venturi meter tube

rate of flow=Q=A1A22g(h1−h2)(A22−A12)  

=6×10×10−42×100×5(−36+100)×10−2

=7.5 cc s-1

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About this question

This is a previous-year question from JEE Main 2014, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.