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JEE Main 2022 — Mathematics in Physics Question with Solution

JEE Main 2022 (28 Jul Shift 2)

Question

In an experiment to find acceleration due to gravity g using simple pendulum, time period of 0.5 s is measured from time of 100 oscillation with a watch of 1 s resolution. If measured value of length is 10 cm known to 1 mm accuracy. The accuracy in the determination of g is found to be x%. The value of x is

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Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

Time period of oscillation is given by T=2πlg , here, l is length and g is acceleration due to gravity.

From above relation, we have  g=14π2T2l.

Fractional error in g is stated as 

Δgg=2ΔTT+Δll

⇒Δgg×100=2×1100×0.5×100+1 mm10 cm×100

⇒Δgg×100=5100×100=5%

Hence, value of x=5.

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About this question

This is a previous-year question from JEE Main 2022, covering the Mathematics in Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.