JEE Main 2025 — Mathematics in Physics Question with Solution
JEE Main 2025 (23 Jan Shift 2)
Question
The energy of a system is given as , where t is the time and . The errors in the measurement of and are and , respectively. At , maximum percentage error in the energy is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
$\begin{aligned}
& d E=3 \alpha^2 d \alpha e^{-\beta t}+\alpha^3 e^{-\beta t}(-\beta) d t \\
& \frac{d E}{E}=\frac{3 d \alpha}{\alpha}+(-\beta) d t \\
& \frac{\Delta E}{E}=\frac{3 \Delta \alpha}{\alpha}+\beta \Delta t
\end{aligned}$
(\%)
Putting values we get
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Mathematics in Physics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2025, covering the Mathematics in Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.