JEE Main 2021PhysicsMathematics in PhysicsMediumNumerical

JEE Main 2021Mathematics in Physics Question with Solution

JEE Main 2021 (16 Mar Shift 1)

Question

The resistance R=VI, where V=50±2 V and I=20±0.2 A. The percentage error in R is x %. The value of x to the nearest integer is ________.

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Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

ΔRR×100=ΔVV×100+ΔII×100

% error in R=250×100+0.220×100

% error in R=4+1

% error in R=5%

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About this question

This is a previous-year question from JEE Main 2021, covering the Mathematics in Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.