JEE Main 2024 — Magnetic Properties Of Matter Question with Solution
From: JEE Main 2024 (Online) 6th April Evening Shift
Question
Match List I with List II:
| LIST I (Y vs X) |
LIST II (Shape of Graph) |
||
|---|---|---|---|
| A. | Y-magnetic susceptibility X = magnetising field |
I. | ![]() |
| B. | Y = magnetic field X = distance from centre of a current carrying wire for x < a (where a = radius of wire) |
II. | ![]() |
| C. | Y = magnetic field distance from centre of a current carrying wire for (where radius of wire) |
III. | ![]() |
| D. | Y = magnetic field inside solenoid X = distance from centre |
IV. | ![]() |
Choose the correct answer from the options given below :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: B
Step-by-step explanation
In para and dia materials, susceptibility is independent of magnetic field.
Inside a current carrying wire,
Outside a current carrying wire,
Inside a solenoid, B is constant upto ends.
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This is a previous-year question from JEE Main 2024, covering the Magnetic Properties Of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.



