JEE Main 2021 — Gravitation Question with Solution
From: JEE Main 2021 (Online) 24th February Morning Shift
Question
Four identical particles of equal masses 1 kg made to move along the circumference of a circle of radius 1 m under the action of their own mutual gravitational attraction. The speed of each particle will be :
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
Given, m = 1 kg, R = 1 m
We know that,
and
Net force on one particle,
As the gravitational force provides the necessary centripetal force, so
Here, FC = centripetal force.
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This is a previous-year question from JEE Main 2021, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.